PHP strtotime returns whole year instead of a single day -



PHP strtotime returns whole year instead of a single day -

i using php round , abs , strtotime calculate difference between 2 dates.

the calculation works until select $_session['b_checkout'] new year. i.e. if b_checkin dec 30 , b_checkout dec 31, returns right $no_nights 1 day.

$_session['b_checkin'] , $_session['b_checkout'] using 'd f js y' date format. e.g.

$_session['b_checkin'] = "wednesday, 31 december, 2014" $_session['b_checkout'] = "thursday, 1 january, 2015" $no_nights = round(abs(strtotime($_session['b_checkout']) - strtotime($_session['b_checkin']))/(60*60*24));

currently outputs (echo $no_nights) 363 days instead of 1 day. problem?

remove commas , see works!

$b_checkin = "wednesday 31 dec 2014"; $b_checkout = "thursday 1 jan 2015"; $no_nights = round(abs(strtotime($b_checkout) - strtotime($b_checkin))/(60*60*24)); echo $no_nights;

when php can't interpret year correctly, uses current year parsing. thats how getting 363 days result.

php strtotime

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