recursion - How to diff all modifications of all checkout files under a directory recursively with Clearcase? -



recursion - How to diff all modifications of all checkout files under a directory recursively with Clearcase? -

it's clearcase.

i checked out several files under directory, of files in sub-directory, in sub-sub-directory.

what want list diff of modifications on these checked out files under directory recursively.

thanks in advance.

updated @ oct 23 2014:

currently figure out 1 solution: for file in $(cleartool lsco -recurse -me -cview -fmt "%n\n"); cleartool diff -serial_format -pred $file; done

i utilize bash loop, if create done simple clearcase command, please update answer, thanks.

the op suggests using list of checked out files, there no way find diff in 1 cleartool command. xargs (used here) might easier

cleartool lsco -recurse -me -cview -fmt "%n\n" | xargs -n 1 cleartool diff -serial_format -pred

recursion diff clearcase

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