recursion - How to diff all modifications of all checkout files under a directory recursively with Clearcase? -
recursion - How to diff all modifications of all checkout files under a directory recursively with Clearcase? -
it's clearcase.
i checked out several files under directory, of files in sub-directory, in sub-sub-directory.
what want list diff of modifications on these checked out files under directory recursively.
thanks in advance.
updated @ oct 23 2014:
currently figure out 1 solution: for file in $(cleartool lsco -recurse -me -cview -fmt "%n\n"); cleartool diff -serial_format -pred $file; done
i utilize bash loop, if create done simple clearcase command, please update answer, thanks.
the op suggests using list of checked out files, there no way find diff in 1 cleartool command. xargs
(used here) might easier
cleartool lsco -recurse -me -cview -fmt "%n\n" | xargs -n 1 cleartool diff -serial_format -pred
recursion diff clearcase
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